We got a blackhole - maybe not

[multitudes]

Important to know for the eval. maybe a bug maybe not?

this metallic red ball if the color is 255,0,0 gives no specular reflection from a blue light ball

C       278,278,-800            0,0,1         60
A       0.1              255,255,255
L      0,250,-50               500             0,0,255 # blue light
sp      90,190,90               180             255,0,0  0  #metallic red

but as soon as the two components are not zero i get the blue specular reflection

C       278,278,-800            0,0,1         60
A       0.1              255,255,255
L      0,250,-50               500             0,0,255 # blue light
sp      90,190,90               180             255,1,1  0  #metallic red

[multitudes]

yeah I checked after the last light refactoring and it still there... pure blue light on pure red metallic gives no reflection?

I asked the AI
gemini:
While pure blue light interacting with a pure red metallic surface might not produce a strong, direct reflection of blue light, it doesn't necessarily mean there's no reflection at all.

Here's a breakdown of what happens:

Absorption: Red metal objects primarily absorb wavelengths of light that are not red, including blue. This means that most of the blue light energy is converted into other forms of energy, like heat.

chatGPT:

it is true that from the  phisics of light,  pure blue light on pure red metallic gives no reflection?
ChatGPT said:
ChatGPT

Yes, that's true based on the physics of light. The reflection you see from a material depends on how the surface interacts with different wavelengths of light.

When pure blue light (which has a wavelength of around 450–495 nm) hits a pure red metallic surface (which typically reflects red light in the 620–750 nm wavelength range), the red metallic surface doesn't reflect blue light efficiently. This is because metals tend to reflect light within a specific color range, which in this case is red. If the blue light is outside the range of wavelengths that the red metallic surface reflects, it won't produce much of a reflection.

In practice, the result is that the red metallic surface will appear very dark or black when illuminated only with blue light because there is little to no reflection of the blue light.